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IBM Developing with IBM Enterprise PL/I Sample Questions:

1. Given the following declarations, which is the WORST way of setting D from 5?
DCL 1 S,
2 A(100) CHAR(1),
2 B(100) CHAR(2),
2 C(100) CHAR(3);
S = "; DCL D CHAR(600);
DCLI BIN FIXED(31);

A) D = STRING(S);
B) D = STRING(A) !! STRING(S) !! STRING(C);
C) DO I = 1 TO 100;
SUBSTR(D,I,1) = S.A(l);
SUBSTR(D,1 01 + ((I-1) *2),2) = S.B(I);
SUBSTR(D,301 + ((I-1) *3),3) = S.C(I);
END;
D) CALL PLIOVER(ADDR(D)ADDR(S),600);

2. Which of the following is NOT a builtin subroutine which supports Logical Unit of Work?

A) PLILUW
B) PLICKPT
C) PLIREST
D) PLICANC

3. In the following example, what value will be written to SYSPRINT, if anything, by the PUT statement in
PGM_A?
PGM_A: PROC;
DCL INPARM CHAR (12) INIT('FIRST CALL? ');
DCL P_OUT PTR;
DCL OUTPARM CHAR (10) BASED (P_OUT);
DCL PGM_B ENTRY (CHAR(12),PTR) EXTEPNAL;
CALL PGM_B (INPARM,P_OUT);
IF OUTPARM = 'YES' THEN
DO;
INPARM = 'FOLLOW ON';
CALL PGM_B (INPARM,P_OUT);
END;
ELSE
DO;
INPARM = 'NORMAL CALL';
CALL PGM_B (INPARM,P_OUT);
END;
PUT SKIP LIST(OUTPARM);
END;
PGM_B: PROC(INPARM,P_OUT);
DCL INPARM CHAR (12);
DCL P_OUT PTR;
DCL OUTPARM CHAR (12) STATIC INIT(");
P_OUT = ADDR(OUTPARM);
IF INPARM = 'FIRST CALL? ' THEN
OUTPARM = 'YES'; ELSE
IF OUTPARM = " THEN
OUTPARM = 'FIRST CALL';
END;

A) The results are unpredictable.
B) blanks
C) 'FIRST CALL'
D) 'YES'

4. Which of the following will definitely NOT cause an unresolved external entry?

A) The main procedure name matching the binder or load module 'name'
B) An incorrect DECLARE for the external entry
C) A mismatch in names between the CALL and the actual procedure
D) Missing library at link time

5. Requirement:
If the value of the numeric variable I is 1 it needs to be changed to 2 and vice versa. In all other cases it
must remain unchanged. Which of the following solutions meets the requirement and does not require
essential structural modifications when the requirement is changed to the following: If the value of the
numeric variable I is 512 it needs to be changed to 731 and if the value is 814 it needs to be changed to 5.
In all other cases it must be set to 111.

A) lF I = 1 ! 1 = 2
THEN I = 3 - I;
B) DCL ONETWO(2) BIN FIXED(15) INIT(2,1);
IF I = 1! I = 2
THEN I = ONETWO(I);
C) SELECT (I);
WHEN(1) I = 2;
WHEN(2) I = 1;
OTHER;
END;
D) IF I = 1 THEN I = 2;
IF I = 2 THEN I = 1;

Solutions: